TURBOLVR
Mr. Whipple
- Joined
- Mar 23, 2008
- Messages
- 2,566
One thing I just thought about is could 1 tooth actually equal 10* or 2.5*? Pump speed is equal to 1/2 engine speed.
2.5* of crank timing.:Cheer:
One thing I just thought about is could 1 tooth actually equal 10* or 2.5*? Pump speed is equal to 1/2 engine speed.
One thing I just thought about is could 1 tooth actually equal 10* or 2.5*? Pump speed is equal to 1/2 engine speed.
One thing I just thought about is could 1 tooth actually equal 10* or 2.5*? Pump speed is equal to 1/2 engine speed.
Ok, so it actually seems like 5* degrees advance on the pump gear would equal 10* on the crank. Each tooth on the crank equals 10*. And you are changing tooth position by 1 tooth. So you are advancing the pump shaft 5* but injection but 10* in relation to the crankshaft. So it seems like 1 tooth is probably about all you would want to advance.
Sean
no. its 2.5*, not 10*.
the crank goes around once, the pump goes around 1/2 revolution. 70 teeth divided by 360* is 5* per revolution of the pump. which is 5* every TWO revs of the crank. 2.5* per single rev.
Nope, no fault codes. We'll see if it makes any gains in power on the dyno.Any fault codes? This is interesting.
so would it be possible at all to have the timing stay at one certain degree??
the only down fall to a p pump is the fixed timing...... why add another fault to a vp44?
some one coild make up a pump gear with weights that move and advance timing based on RPM, probably wouldnt be all that hard either, now to find some one with a bunch of money and a good machine shop with some spare time