I trying to understand why guys need jumbo beer coolers with 120lbs of ice for 1000-1200hp.
Ive seen the intercooler system used by a mod truck, the core is large, but only requires 40lbs of ice and few gallons of water to keep up with 2000+hp.
For a simple equation, the air entering the core is a steady 400 degrees exits a steady 80, and you flow 60GPM of 32 degree water, the water temperature is going to have to raise to X degrees to maintain that equation.
Now, if you are limited to half the flow, only 30GPM, and you still achieve the same 400 inlet, 80 outlet temps, Would temperature of the water exiting the core be doubled as its carrying a greater amount of energy at a slower rate?
What I am trying to figure out is how the equation works out that if I can flow a larger volume through the core, would I be able to get away with less ice because the temperature of the water returning to the reservoir would be lower, and not melt the ice as fast.
This stuff makes me want to go back to school, or start reading text books.